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11 April, 11:59

Calculate the [oh-] in a solution with a ph of 12.52.

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  1. 11 April, 13:38
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    PH + pOH = 14

    12.52 + pOH = 14

    pOH = 14 - 12.52

    pOH = 1.48

    [OH⁻] = 10^ - pOH

    [OH⁻] = 10 ^ - 1.48

    [OH⁻] = 0.033 M
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