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26 July, 08:57

If there are 160 Calories in 28 g in 1 serving of Flamin' Hot Cheetos, how many gram (s) of Cheetos must you burn to raise the temperature of 20.0 mL of water 1oC?

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  1. 26 July, 12:12
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    3.5 g

    Explanation:

    The density of water is 1 g/mL. The mass (m) corresponding to 20.0 mL is 20.0 g.

    We can calculate the heat (Q) required to raise the temperature of 20.0 mL of water 1 °C (ΔT).

    Q = c * m * ΔT = 1 cal/g.°C * 20.0 g * 1 °C = 20 cal

    where,

    c is the specific heat capacity of water

    There are 160 calories in 28 g of Cheetos. The mass that releases 20 cal is:

    20 cal * (28 g/160 cal) = 3.5 g
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