Ask Question
5 August, 01:06

Aluminum had a specific heat of 0.215 cal / (g °C). When 25.7 cal (108.5 J) of heat is added to 18.4 g of aluminum at 20.0°C, what is the final temperature of the aluminum?

+5
Answers (1)
  1. 5 August, 03:23
    0
    26.5°C

    Explanation:

    Heat added is the product of mass, specific heat capacity, and change in temperature.

    q = mC (T - T₀)

    25.7 cal = (18.4 g) (0.215 cal/g/°C) (T - 20.0°C)

    T = 26.5°C
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Aluminum had a specific heat of 0.215 cal / (g °C). When 25.7 cal (108.5 J) of heat is added to 18.4 g of aluminum at 20.0°C, what is the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers