A sample of natural gas contains 8.24 moles of CH4, 0.421 moles of C2H6, and 0.116 moles of C3H8. If the total pressure of the gases is 1.37 atm, what is the partial pressure of propane (C3H8)

The partial pressure of propane is 0.018 atm

Explanation:

Moles of propane = 0.116 moles

Total moles of gas mixture = 8.24+0.421+0.116 = 8.777 moles

Total pressure of gas mixture = 1.37 atm

Partial pressure of propane = 0.116/8.777 * 1.37 atm = 0.018 atm