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27 April, 21:57

Which of the following gives the molarity of a 17.0% by mass solution of sodium acetate, CH 3COONa (molar mass = 82.0 g/mol) in water? The density of the solution is 1.09 g/mL. a. 2.26 * 10^-6 M b. 0.207M c. 2.07M d. 2.26M e. 2.72M

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  1. 28 April, 01:12
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    The molarity of this solution is 2.26 M (option D)

    Explanation:

    Step 1: Data given

    Mass % = 17%

    Molar mass of CH3COONa = 82.0 g/mol

    Density of the solution = 1.09 g/mL

    Step 2:

    Assume the mass of the solution is 1.00 gram

    ⇒ 17.0 % CH3COONa = 0.17 grams

    ⇒ 83.0 % H2O = 0.83 grams

    Step 3:

    Density = 1.09 g/mL

    Volume of the solution = total mass / density of solution

    Volume of solution : 1.00 grams / 1.09 g/mL

    Volume of the solution = 0.917 mL = 0.000917 L

    Step 4: Calculate number of moles of CH3COONa

    Number of moles = Mass / molar mass

    Number of moles CH3COONa = 0.170 grams / 82.0 g/mol

    Number of moles = CH3COONa = 0.00207 moles

    Step 5: Calculate molarity

    Molarity = moles / volume

    Molarity solution = 0.00207 / 0.000917 L

    Molarity solution = 2.26 mol/L = 2.26 M

    The molarity of this solution is 2.26 M (option D)
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