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2 January, 10:10

If a 3.6 moles of an ideal gas occupies 150 mL tank at a temperature of - 5 °C, what is the pressure inside the tank?

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  1. 2 January, 12:27
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    528.086 atm

    Explanation:

    We are given;

    The number of moles of an ideal gas as 3.6 moles

    Volume occupied by the gas is 150 mL or 0.15 L

    Temperature of the gas is - 5° C

    But, K = °C + 273.15

    Therefore, Temperature, T = 268.15 K

    We are required to calculate the pressure in the tank.

    In this case we are going to use the ideal gas equation;

    The ideal gas equation states, PV = nRT, where P is the pressure, v is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant, 0.082057 L. atm/mol. K Therefore, rearranging the equation we can find the pressure in the tank.

    P = nRT: V

    = (3.6 mole * 0.082057 * 268.15 K) : 0.15 L

    =528.086 atm

    Therefore, the pressure in the tank is 528.086 atm
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