If a 3.6 moles of an ideal gas occupies 150 mL tank at a temperature of - 5 °C, what is the pressure inside the tank?

528.086 atm

Explanation:

We are given;

The number of moles of an ideal gas as 3.6 moles

Volume occupied by the gas is 150 mL or 0.15 L

Temperature of the gas is - 5° C

But, K = °C + 273.15

Therefore, Temperature, T = 268.15 K

We are required to calculate the pressure in the tank.

In this case we are going to use the ideal gas equation;

The ideal gas equation states, PV = nRT, where P is the pressure, v is the volume, n is the number of moles, T is the temperature and R is the ideal gas constant, 0.082057 L. atm/mol. K Therefore, rearranging the equation we can find the pressure in the tank.

P = nRT: V

= (3.6 mole * 0.082057 * 268.15 K) : 0.15 L

=528.086 atm

Therefore, the pressure in the tank is 528.086 atm