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21 May, 01:15

5. If 30mL of 0.5M NaOH (aq) was used to neutralize 10mL of HCl (aq), what is the concentration of the acid? Show work.

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  1. 21 May, 05:14
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    0.15M

    Explanation:

    NaOH + HCl - ->NaCl + H2O

    moles of NaOH reacted with HCl

    (0.5 * 30) / 1000 = 1.5 * 10^ - 3

    so the moles of HCl reacted with NaOH

    1.5 * 10^ - 3

    concentration of HCl = (1.5 * 10^ - 3) / 10 * 1000
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