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18 July, 16:40

How many grams of Fe is needed to react with 35.0 g of sulfuric acid in the following reaction? 3H2SO4 + 2Fe - > Fe2 (SO4) 3 + 3H2

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  1. 18 July, 17:45
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    13.3 g

    Explanation:

    Let's consider the following reaction.

    3 H₂SO₄ + 2 Fe → Fe₂ (SO₄) ₃ + 3 H₂

    The molar mass of H₂SO₄ is 98.1 g/mol. The moles of H₂SO₄ in 35.0 g are:

    35.0 g * (1 mol / 98.1 g) = 0.357 mol

    The molar ratio of H₂SO₄ to Fe is 3:2. The moles of Fe are:

    0.357 mol H₂SO₄ * (2 mol Fe / 3 mol H₂SO₄) = 0.238 mol

    The molar mass of Fe is 55.8 g/mol. The mass of Fe is:

    0.238 mol * (55.8 g/mol) = 13.3 g
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