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27 August, 07:18

The specific heat capacity of lead is 0.130 J/g-K. How much heat

is required to raise the temperature of 15.0 g of lead from 22.0 °C

to 37.0 °C?

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Answers (1)
  1. 27 August, 09:03
    0
    Q = 29.2 J

    Explanation:

    22°C=295K

    37°C=310K

    Q = mC dT

    Q = (15.0 g) * (0.130 J/g-K) * (310 K-295K)

    Q = 29.2 J
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