What is the pressure in atmospheres of 6.0 moles

of an ideal gas if its volume is 2.0 liters and its

temperature is at 80.0°C? Record your answer to

the nearest atmosphere.

Answer: 87atm

Explanation:

Ideal gas equation is given by the formular: PV = nRT

P = ? V = 2L, n = 6moles

R = 0.082057 L. atm/mol/K

T = 80° C + 273.15 = 353.15K

Let's make 'P', the subject of formula,

P = nRT / V

= 6mol x 0.082057 L. atm/mol/K.

x 353.15K / 2L

= 86.9 approximately

= 87atm