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Ammonia (NH3) is one of the most common chemicals produced in the united states. it is used to make fertilizer and other products. Ammonia is produced by the following chemical reaction. N2 (g) + 3h2 (g) = 2nh3 (g) If you have 1.00 x 10^3g of N2

a. If you have 1.00 x 10'g of N2 and 2.50 x 10' of H2, which is the limiting reactant in the reaction?

b. How many grams of ammonia can be produced from the amount of limiting reactant available?

c. Calculate the mass of excess reactant that remains after the reaction is complete.

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  1. Today, 09:41
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    a) N2 is the limiting reactant

    b) 1215.9 grams NH3

    c) 2283.6 grams H2

    Explanation:

    Step 1: Data given

    Mass of N2 = 1000 grams

    Molar mass N2 = 28 g/mol

    Mass of H2 = 2500 grams

    Molar mass H2 = 2.02 g/mol

    Step 2: The balanced equation

    N2 (g) + 3H2 (g) → 2NH3 (g)

    Step 3: Calculate moles N2

    Moles N2 = mass N2 / molar mass N2

    Moles N2 = 1000 grams / 28.0 g/mol

    Moles N2 = 35.7 moles

    Step 4: Calculate moles H2

    Moles H2 = 2500 grams / 2.02 g/mol

    Moles H2 = 1237.6 moles

    Step 5: Calculate limiting reactant

    For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

    N2 is the limiting reactant. There will be consumed 35.7 moles.

    H2 is in excess. There will react 3*35.7 = 107.1 moles

    There will remain 1237.6 - 107.1 = 1130.5 moles H2

    This is 1130.5 * 2.2 = 2283.6 grams H2

    Step 6: Calculate moles NH3

    For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

    For 35.7 moles N2 we'll have 2*35.7 = 71.4 moles NH3

    Step 7: Calculate mass NH3

    Mass NH3 = moles NH3 * molar mass NH3

    Mass NH3 = 71.4 moles * 17.03 g/mol

    Mass NH3 = 1215.9 grams NH3
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