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19 September, 23:32

How many moles of ZnCl, will be produced from 23.0 g of Zn, assuming CuCl, is available in excess?

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  1. 20 September, 03:29
    0
    23 g of Zn will produce 0.352 mole of zinc chloride.

    Explanation:

    Given dа ta:

    mass of Zn = 23 g

    Moles of ZnCl = ?

    Solution:

    Chemical equation:

    2Zn + CuCl₂ → 2ZnCl + Cu

    Number of moles of Zn:

    Number of moles of Zn = mass / molar mass

    Number of moles of Zn = 23 g / 65.38 g/mol

    Number of moles of Zn = 0.352 mol

    now we will compare the moles of ZnCl with Zn because it is limiting reactant.

    Zn : ZnCl

    2 : 2

    0.352 : 0.352

    So 23 g of Zn will produce 0.352 mole of zinc chloride.
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