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5 August, 21:16

What is the correct balanced equation for the following:

potassium iodide + lead (II) sulfide - -> lead (ii) iodide + potassium sulfide

(A) 2KI + PbS - > Pbl2, + K2S

(B) KI + PbS-> Pbl + KS

(C) KI + Pb25 - > Pb2l + KS

(D) 2KI + Pb25 - > Pb2l2 + K2s

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  1. 5 August, 22:53
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    A)

    K has a positive charge of 1

    I has a negative charge of 1

    S has a negative charge of 2

    Pb has a positive charge of 2

    2KI + PbS - > PbI2 + K2S
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