If a gas's [kelvin] temperature doubles and it's volume then remains the same, then what happens to it's pressure?

The final pressure will double i. e it will be twice the initial pressure

Explanation:

T1 = T

T2 = 2T (twice the original T)

P1 = P

P2 = ?

Since the volume is constant,

P1 / T1 = P2 / T2

P / T = P2 / 2T

Cross multiply

T x P2 = 2T x P

Divide both side by T

P2 = (2T x P) / T

P2 = 2P

Therefore, the final pressure will double i. e it will be twice the initial pressure