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15 February, 01:48

The following volumes of solution are combined in a test tube: 2.00 mL of 0.20 M potassium iodide 1.00 mL of 1% starch 0.50 mL of 0.20 M ammonium persulfate 0.50 mL of 0.012 M sodium thiosulfate 2.00 mL of 0.20 M potassium nitrate 2.00 mL of 0.20 M ammonium sulfate What is the concentration of iodide in the solution in the test tube?

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  1. 15 February, 03:49
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    The answer to your question is: Concentration = 0.05 M

    Explanation:

    Data

    2ml of KI 0.2M

    1 ml 1% starch

    0.5 ml 0.2 M ammonium persulphate

    0.5 ml 0.012 M sodium thiosulphate

    2 ml 0.2 M potassium nitrate

    2 ml 0.2 M ammonium nitrate

    Formula to calculate moles of KI

    Molarity = moles / volume

    moles = Molarity x volume

    moles = (0.2) (0.002)

    moles = 0.0004

    Total volume = 2 + 1 + 0.5 + 0.5 + 2 + 2 = 8 ml

    Molarity = 0.0004 / 0.008

    Molarity = 0.05
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