Calculate the volume of 0.413 mol of hydrogen gas at a temperature of 20°C and a pressure of 1200 torr.

The volume is 6, 28 liters

Explanation:

The unit of pressure and temperature must be converted. 760 Torr = 1 atm and 0°C=273 K. 20+273=293K

760 Torr---1 atm

1200Torr--x = (1200 Torr x 1 atm) / 760 Torr = 1,58 atm

PV=nRT V = (nRT) / P

V = (0,413 mol x 0,082 L atm / K mol x 293K) / 1,58 atm

V=6, 28 L