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28 December, 02:45

How many grams of KOH are present in 29.5 mL of a 6.82 V KOH solution?

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Answers (1)
  1. 28 December, 03:39
    0
    Mass of KOH = 11.48 g

    Explanation:

    Given dа ta:

    Molarity of KOH = 6.82 M

    Volume = 29.5 mL (0.03 L)

    Mass of KOH = ?

    Solution:

    Number of moles = molarity * volume

    Number of moles = 6.82 M * 0.03 L

    Number of moles = 0.205 mol

    Mass:

    Mass of KOH = number of moles * molar mass

    Mass of KOH = 0.205 mol * 56 g/mol

    Mass of KOH = 11.48 g
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