Ask Question
9 November, 02:04

When aluminum oxidizes in air, it forms aluminum oxide (Al2O3):

4Al (s) + 3O2 (g) →2Al2O3 (s)

A 102 g sheet of aluminum oxide formed completely in excess oxygen.

How many grams of aluminum were oxidized?

27 g

51 g

54 g

102 g

54 is correct answer

+5
Answers (1)
  1. 9 November, 04:25
    0
    54 g of Aluminium were oxidized

    Explanation:

    The equation for the reaction:

    4Al (s) + 3O₂ (g) →2Al₂O₃ (s)

    We are required to calculate the mass of Aluminium that reacted;

    Step 1: Calculating the number of moles Aluminum oxide

    Mass of Aluminium oxide = 102 g

    Molar mass of Al₂O₃ = 101.96 g/mol

    Number of moles = Mass : Molar mass

    = 102 g : 101.96 g/mol

    = 1 mole

    Step 2: Number of moles of Aluminium oxidized

    From the equation, the mole ratio of Al to Al₂O₃ is 4 : 2

    Therefore; Moles of Al is (4/2) (1) is 2 moles

    2 moles of Aluminium were oxidized

    Step 3: Mass of Aluminium oxidized

    Mass = Number of moles * Molar mass

    Molar mass of Aluminium is 27 g/mol

    Therefore;

    Mass of Aluminium = 2 moles * 27 g/mol

    = 54 g

    Therefore, 54 g of Aluminium were oxidized
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “When aluminum oxidizes in air, it forms aluminum oxide (Al2O3): 4Al (s) + 3O2 (g) →2Al2O3 (s) A 102 g sheet of aluminum oxide formed ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers