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29 April, 04:01

4fe (s) + 3o2 (g) →2fe2o3 (s) how many grams of Fe2O3 are produced when 12.0 of iron rusts

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  1. 29 April, 06:32
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    Mass = 10.1 g

    Explanation:

    Given dа ta:

    Mass of Fe₂O₃ produced = ?

    Mass of iron rust = 12.0 g

    Solution:

    Chemical equation:

    4Fe + 3O₂ → 2Fe₂O₃

    Number of moles of iron:

    Number of moles = mass / molar mass

    Number of moles = 12.0 g / 55.85 g/mol

    Number of moles = 0.215 mol

    Now we will compare the moles of iron and Fe₂O₃.

    Fe : Fe₂O₃

    4 : 2

    0.215 : 2/4*0.125 = 0.063 mol

    Mass of Fe₂O₃:

    Mass = number of moles * molar mass

    Mass = 0.063 mol * 159.7 g/mol

    Mass = 10.1 g
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