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16 February, 12:28

What is the mass (in grams) of 9.07 * 1024 molecules of methanol (CH3OH) ?

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  1. 16 February, 12:51
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    N=N/Na

    =9.07x10^ (24) / 6.02x10^ (23)

    = 15.1mol

    m=n x M (molar mass of CH3OH is 32.05 g/Mol)

    = 15.1 x 32.05

    =484g
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