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13 December, 06:10

What volume of 0.6 m hcl is required to neutralize 100.0 ml of 0.5 m naoh?

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  1. 13 December, 09:21
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    In order to determine the amount needed, we have to know the chemical reaction that would happen between the substances. In this case the reaction would be:

    NaOH + HCl = NaCl + H2O

    We calculate as follows:

    .1 L (0.5 mol NaOH / L) (1 mol HCl / 1 mol NaOH) (1 L / 0.6 mol HCl) = 0.08 L or 80 mL of 06 M HCl

    Hope this answers the question. Have a nice day.
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