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4 August, 11:35

In the reaction MgCl2 + 2KOH Mg (OH) 2 + 2KCl, if 3 moles MgCl2 are added to 4 moles KOH, what determines how much Mg (OH) 2 is made?

A. The amount of MgCl2 + KOH

B. The amount of KCl

C. The amount of MgCl2

D. The amount of KOH

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  1. 4 August, 11:59
    0
    The correct option is C. The amount of MgCl2. we know this because no matter how much you increase KOH, if you dont increase Mgcl2, the amount of Mg (OH) 2 remains the same. Hope this works for you
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