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15 October, 02:33

How many ammonium ions and how many sulfate ions are present in an 0.260 mol sample of (nh4) 2so4?

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  1. 15 October, 05:36
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    The question requires that you assume complete ionization of the compound. This is:

    (NH4) 2 SO4 → 2 NH4 (+) + SO4 (2-)

    Then, 1 mol of (NH4) 2 SO4 produces 3 moles of ions: 2 moles of NH4 (+) and 1 mol of SO4 (2-)

    => 0.26 * 2 moles of NH4 (+) = 0.52 moles of NH4 (+)

    0.26 * 1 mol of SO4 (2-) = 0.26 moles of SO4 (2-).

    Answer: 0.52 moles of ammonium ions and 0.26 moles of sulfate. ions.
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