You place a balloon in a closed chamber at standard temperature and pressure (STP). You cool the chamber to half of its original temperature while leaving the pressure constant. What happens to the balloon?

It stays the same volume.

It decreases to one-half of its original volume.

It doubles in volume.

It expands to four times its original volume.

Question

Chemistry

Essence Baird

24 February, 03:09

You place a balloon in a closed chamber at standard temperature and pressure (STP). You cool the chamber to half of its original temperature while leaving the pressure constant. What happens to the balloon?

It stays the same volume.

It decreases to one-half of its original volume.

It doubles in volume.

It expands to four times its original volume.

+5

Answers (2)

Know the Answer?

Brody Pham · Answer 1

It decreases to one half of its original volume.

Tiana Schaefer · Answer 2

I think the correct answer from the choices listed above is the second option. At constant temperature, the volume of the system at the new conditions will decrease to one-half of its original volume.

V1 = nRT1 / P

V2 = nRT1 / 2P = 2V1