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12 March, 13:06

How many joules are needed to warm 45.0 grams of water from 30.0 degrees C to 75.0 degrees C?

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  1. 12 March, 15:15
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    Q=m x Cp x ∆T

    m is the mass of the water, Cp is the specific heat of water and ∆T is the change in temperature of the water (final-initial temperature). q is the energy involved in the reaction, measured in joules.

    q = (45.0) x (4.184 Jg^-1/°C^-1) x (45°C)

    q=8472.6 Joules
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