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30 August, 23:19

A nuclide of 64/29 cu absorbs a positron. witch is the resulting atom

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  1. 31 August, 01:02
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    We are given a nuclide 64Cu29 which absorbs a positron. A positron is an alpha particle with a symbol of 4α2. So, the nuclear reaction is:

    64Cu29 + 4α2 = = = > 68Er31

    The resulting atom is an Erbium with an atomic number of 68.
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