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15 July, 07:25

What is the ph of a 0.15 m solution of ammonium chloride?

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  1. 15 July, 09:07
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    Best Answer: (a)

    8.9 x 10^-7 = x^2 / 0.15-x

    x = [OH-] = 0.00037 M

    pOH = 3.4

    pH = 14 - 3.4 = 10.6

    (b)

    Ka = Kw/Kb = 5.6 x 10^-10 = x^2 / 0.20-x

    x = [H+] = 0.000011 M

    pH = 5.0
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