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2 February, 09:00

An aqueous solution at 27°c contains 3.6 g of a protein in a 200 ml sample. the osmotic pressure is 0.0203 atm. what is the molar mass of the protein

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  1. 2 February, 11:14
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    In order to calculate the molar mass of the protein, we may manipulate the ideal gas equation:

    PV = nRT, where n is the number of moles. We also know that:

    n = m / Mr, where m is mass and Mr is molecular weight

    Thus,

    Mr = (mRT) / (PV)

    Here, the mass is in grams, the temperature is in Kelvin, the pressure is in atm and the volume is in liters, so the molar gas constant is 0.082057.

    Mr = (3.6 * 0.082057 * (27 + 273)) / (0.0203 * 0.2)

    Mr = 21,828 g/mol

    Thus, the Mr of the protein is 2.18 x 10⁴ g/mol
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