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4 December, 12:22

Having difficulty understanding formulas involved. Determine the quantity (g) of pure CaCl2 in 7.5 g of CaCl2•9H2O.

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  1. 4 December, 13:30
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    To determine the quantity of pure CaCl2 from the given amount of CaCl2.9H2O, we use the ratio of CaCl2 to CaCl2.9H2O. From the formula the ratio would 1 is to 1 We calculate as follows:

    7.5 g CaCl2.9H2O (1 mol / 273.1215 g) (1 mol CaCl2 / 1 mol CaCl2.9H2O) (110.98 g / 1 mol) = 3.05 g CaCl2

    Hope this answers the question. Have a nice day. Feel free to ask more questions.
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