A solution is 40% acetic acid by mass. The density of this solution is 1.049 g/mL. Calculate the mass of pure acetic acid in 360 mL of this solution at 20 C. Answer in units of g.

151.056 g A. Acid pure.

Explanation:

First, we going to change mL to grams using the density:

1.049 g / mL means that 1 mL of solution weight 1.049 g:

360 mL x (1.049 g / 1 mL) = 377.64 g Solution.

Then. we have to find the amount of pure acetic acid we have.

A solution at 40 % means that for 100 g of the solution just 40 g is pure acetic acid:

377.64 g solution x (40 g acetic acid/100 g solution) = 151.056 g A. Acid pure.