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23 January, 18:41

A gas occupies 11.2L at 0.860kPa. What is the pressure if the volume

becomes 15.0L

A) 0.64L

B) 1.2kPa

C) 0.64kPa

D) 1.2L

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Answers (2)
  1. 23 January, 19:28
    0
    Answer: Option C) 0.64kPa

    Explanation:

    Given that,

    Original volume V1 = 11.2 L

    original pressure P1 = 0.860kPa

    New volume V2 = 15.0 L

    New pressure P2 = ?

    Since pressure and volume are involved while temperature is constant, apply Boyle's law

    P1V1 = P2V2

    0.860 kPa x 11.2 L = P2 x 15.0L

    9.632 kPaL = P2 x 15.0L

    P2 = 9.632 kPaL / 15.0L

    P2 = 0.64 kPa

    Thus, the pressure of the gas is 0.64kPa
  2. 23 January, 21:17
    0
    The correct answer is C) 0.64kPa
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