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2 May, 20:49

If the pressure of a gas is 1.50 atm, its volume is 2.50 L, and its temperature is 22, what is the volume if the pressure is increased to 3.00 atm and the temperature is increased ton35

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  1. 3 May, 00:23
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    The answer to your question is V2 = 1.3 l

    Explanation:

    Data

    Pressure 1 = P1 = 1.5 atm

    Volume 1 = V1 = 2.50 l

    Temperature 1 = T1 = 22°C

    Pressure 2 = P2 = 3 atm

    Volume 2 = V2 = ?

    Temperature 2 = T2 = 35°C

    Process

    1. - Convert temperature to °K

    T1 = 22 + 273 = 295°K

    T2 = 35 + 273 = 308°K

    2. - Use the combine gas law to solve this problem

    P1V1/T1 = P2V2/T2

    -Solve for V2

    V2 = P1V1T2 / T1P2

    3. - Substitution

    V2 = (1.5 x 2.5 x 308) / (295 x 3)

    4. - Simplification

    V2 = 1155 / 885

    5. - Result

    V2 = 1.3 l
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