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9 November, 07:03

How many moles of oxygen are present in 33.6l of the gas at 1atm and 0c

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  1. 9 November, 08:21
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    The answer is: 1.5 moles of oxygen are present.

    V (O₂) = 33.6 L; volume of oxygen.

    p (O₂) = 1.0 atm; pressure of oxygen.

    T = 0°C; temperature.

    Vm = 22.4 L/mol; molar volume at STP (Standard Temperature and Pressure).

    At STP one mole of gas occupies 22.4 liters of volume.

    n (O₂) = V (O₂) : Vm.

    n (O₂) = 33.6 L : 22.4 L/mol.

    n (O₂) = 1.50 mol; amount of oxygen.
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