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27 November, 17:18

A sample of a gas has a volume if 852mL at 288K. What temperature did s necessary for the gas to have a volume of 945mL?

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Answers (1)
  1. 27 November, 18:49
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    The answer to your question is T2 = 319.4°K

    Explanation:

    Data

    Volume 1 = V1 = 852 ml

    Temperature 1 = T1 = 288°K

    Volume 2 = V2 = 945 ml

    Temperature 2 = T2 = ?

    Process

    To solve this problem, use Charles' law.

    V1/T1 = V2/T2

    -Solve for T2

    T2 = V2T1/V1

    -Substitution

    T2 = (945 x 288) / 852

    -Simplification

    T2 = 272160 / 852

    -Result

    T2 = 319.4°K
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