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24 March, 21:51

What is the equilibrium constant for the following reaction at 25°C?

Mg (s) + Zn2 + (aq) = Mg2 + (aq) + Zn (s)

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  1. 25 March, 00:23
    0
    2.45*10^54

    Explanation:

    Mg (s) + Zn2 + (aq) = Mg2 + (aq) + Zn (s)

    From the equation;

    n = 2 moles of electrons

    E°anode = - 2.37 V

    E°cathode = - 0.76 V

    From E°Cell = E°cathode - E°anode

    E°Cell = - 0.76 - (-2.37) = 1.61 V

    Recall that E°cell = 0.0592/n log K

    1.61 = 0.0592/2 log K

    log K = 1.61/0.0296

    K = Antilog (54.39)

    K = 2.45*10^54
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