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20 April, 23:25

2.26 g of liquid water at 23.5 ◦C was com - pletely converted to ice at 0 ◦C. How much heat was (absorbed/released) by the system during this process?

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  1. 21 April, 03:17
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    Givens

    m = 2.26 g

    c = 4.19 J / (g * oC)

    Δt = 23.5oC - 0 = 23.5oC

    hf = heat of fusion for ice = 334 J/g

    Equation

    H = m*c*Δt + hf * m

    H = m * (c*Δt + hf)

    Solution

    H = 2.26 * (4.19 * 23.5 + 334)

    H = 2.26 * (432.5)

    H = 977.4 J
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