the diagram below represents two beakers, each containing an ice cube and clear liquid. in beaker A the ice cube floats, and in beaker B the ice cube rest on the bottom. what is the most probable cause for the difference in behavior of the ice cube in the two beakers?

Question

Chemistry

Flopsy

9 March, 20:35

the diagram below represents two beakers, each containing an ice cube and clear liquid. in beaker A the ice cube floats, and in beaker B the ice cube rest on the bottom. what is the most probable cause for the difference in behavior of the ice cube in the two beakers?

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Answers (1)

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Braxton Armstrong · Answer 1

The density of the liquid in beaker B is less than the that of ice.

Explanation:

Ice will float if its mass is less than the mass of the liquid it displaces.

For example, the density of ice is less than that of water.

A 10 cm³ cube of ice has a mass of about 9 g, while the mass of 10 cm³ of water is 10 g. Thus, 9 g of ice displaces 10 g of water.

The denser water displaces the lighter ice and the ice floats to the top.

If the density of the liquid is less than that of water, say, 8 g/cm³, the ice will displace only 8 g of the liquid. The ice will sink.