What is 4.2 moles of lithium fluoride are dissolved in 200 lliliters of solution in molarity?

In this question we have to find the molarity of lithium floride (LiF)

This can be calculated by formula

Molarity=moles of solute/liters of solution

In given data

Mole of solute=4.2mole of LiF

Liter of solution = 200mL=200/1000=0.2liter

M=4.2/0.2=21M solution of lithium fluoride

21 mol·L⁻¹

Step-by-step explanation:

dа ta:

n = 4.2 mol

V = 200 mL

Calculation:

c = moles/litres = n/V

V = 200 mL Convert to litres

V = 200 mL * (1 L/1000 mL)

V = 0.200 L

c = 4.2/0.200

c = 21 mol·L⁻¹

Note: This is an impossible value. Even at 100 °C, the solubility of NaF is only about 2 mol·L⁻¹.