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23 January, 16:56

5. An aluminum (Aℓ) cylinder is 10.0 cm in length and has a radius of 2.5 mm. If the mass of a single Aℓ atom is 4.48 x 10-23 g, calculate the number of Aℓ atoms present in the cylinder. The density of aluminum is 2.70 g/cm3. (Volume of a cylinder = π r2 ℓ and π=3.14)

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  1. 23 January, 19:25
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    1.2 x 1023 atoms
  2. 23 January, 19:26
    0
    Answer;

    = 1.183 * 10^25 atoms

    Explanation;

    Volume of a cylinder is given by the formula;

    πr²h, where r is the radius, and h is the height or length.

    Volume = 3.14 * 2.5² * 10

    = 196.25 cm³

    But density = 2.7 g/cm³

    Therefore;

    Mass = volume * density

    = 196.25 * 2.7

    = 529.875 g

    But; 1 atom = 4.48 x 10-23 g

    Therefore;

    Number of atoms = 529.875 g / 4.48 x 10-23 g

    = 1.183 * 10^25 atoms
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