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24 July, 20:43

For the reaction 2H2O (g) ↽--⇀2H2 (g) + O2 (g) the equilibrium concentrations were found to be [H2O]=0.250 M, [H2]=0.300 M, and [O2]=0.750 M. What is the equilibrium constant for this reaction?

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  1. 24 July, 21:42
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    1.08

    Explanation:

    Step 1:

    Data obtained from the question. This includes:

    [H2O] = 0.250 M

    [H2] = 0.300 M

    [O2] = 0.750 M

    Equilibrium constant, K = ?

    Step 2:

    Equation for the reaction.

    2H2O (g) 2H2 (g) + O2 (g)

    Step 3:

    Determination of the equilibrium constant.

    The equilibrium constant for the above equation is written as fallow:

    K = [H2]^2 [O2] / [H2O]^2

    K = (0.3) ^2 x 0.75 / (0.250) ^2

    K = 1.08

    Therefore, the equilibrium constant for the above reaction is 1.08
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