What is the pOH of a 2.70 x 10^-11 M Solution of lithium hydroxide (LIOH) ?

Question

Chemistry

Adolfo Parks

13 April, 09:13

What is the pOH of a 2.70 x 10^-11 M Solution of lithium hydroxide (LIOH) ?

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Answers (1)

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Miles Fritz · Answer 1

The POH of a 2.70 x10^-11 solution of lithium hydroxide (LiOH) is 10.6

calculation

POH = - log (OH-)

write the equation for dissociation of LiOH

LiOh---> Li^ + (aq) + OH - (aq)

from the equation above the ratio LiOH: OH is 1:1 therefore the concentration of OH - = 2.70 x10 ^-11

that is - log (2.70 x10^-11) = 10.6