17. A gas tank holds 2785 L of propane, C3H8, at 830. mm

Hg. What is the

volume of the propane at standard pressure?

3041.5L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 2785 L

P1 (initial pressure) = 830mmHg

P2 (final pressure) = stp = 760mmHg

V2 (final volume) = ?

Applying the Boyle's law equation P1V1 = P2V2, the final volume propane can be achieved by as illustrated below:

P1V1 = P2V2

830 x 2785 = 760 x V2

Divide both side by 760

V2 = (830 x 2785) / 760

V2 = 3041.5L

Therefore, the volume of the propane at standard pressure is 3041.5L