Ask Question
19 March, 05:51

1 - A gas occupies a volume of 4.0 L at 2.5 kPa. What volume will the gas occupy at 20.0 kPa?

I

+5
Answers (2)
  1. 19 March, 06:15
    0
    0.5 L

    Explanation:

    V1 (initial volume) = 4 L

    P1 (initial pressure) = 2.5 kPa

    P2 (final pressure) = 20 kPa

    V2 (final volume) = ?

    Use Boyle's law P1V1 = P2V2, to find the the final volume

    P1V1 = P2V2

    2.5 x 4 = 20 x V2

    Divide both side by 20

    V2 = (2.5 x 4) / 20

    V2 = 0.5 L
  2. 19 March, 07:12
    0
    Answer: 0.5L

    Explanation:

    Using Boyle's law

    P1V1=P2V2

    P1 = 2.5kpa

    V1 = 4l

    V2=?

    P2 = 20.0kpa

    Substitute the value into this formula

    P1V1=P2V2

    2.5*4=20*V2

    Cross multiply

    2.5*4=20V2

    V2 = 2.5*4/20

    V2 = 80/2.5

    V2 = 0.5L

    So 0.5L of gas will occupy 20.0kpa
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “1 - A gas occupies a volume of 4.0 L at 2.5 kPa. What volume will the gas occupy at 20.0 kPa? I ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers