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20 September, 12:01

A mixture of krypton and hydrogen gases, at a total pressure of 692 mm Hg, contains 20.9 grams of krypton and 0.133 grams of hydrogen. What is the partial pressure of each gas in the mixture?

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  1. 20 September, 15:47
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    Partial pressure Kr → 546.1 mmHg

    Partial pressure H₂ → 145.9 mmHg

    Explanation:

    To determine the partial pressure of each gas in the mixture we apply the mole fraction concept.

    Mole fraction → Moles of gas / Total gas = Partial pressure / Total pressure

    In this mixture: Partial pressure Kr + partial pressure H₂ = 692 mmHg

    We determine the moles of each:

    20.9 g / 83.80 g/mol = 0.249 moles Kr

    0.133 g / 2 g/mol = 0.0665 moles H₂

    Total moles: 0.249 moles Kr + 0.0665 moles H₂ = 0.3155 moles

    Mole fraction Kr → 0.249 mol / 0.3155 mol = 0.789

    Partial pressure Kr → 0.789. 692mmHg = 546.1 mmHg

    Partial pressure H₂ → 692mmHg - 546.1 mmHg = 145.9 mmHg
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