What is the volume of 7.25 g of oxygen gas at STP?

5.15 L

Step-by-step explanation:

This looks like a case where we can use the Ideal Gas Law to calculate the volume.

pV = nRT Divide both sides by p

V = (nRT) / p

dа ta:

m = 7.25 g

R = 0.083 14 L·atm·K⁻¹mol⁻¹

T = (0 + 273.15) K = 273.15K

p = 1 bar (Note: STP is 1 bar and 0°C)

Calculations:

(a) Moles of O₂

n = m/M

n = 7.25/32.00

n = 0.2266 mol

(b) Volume

V = (0.2266 * 0.083 14 * 273.15) / 1

V = 161.3/2.00

V = 5.15 L