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13 June, 22:33

What is the volume of 7.25 g of oxygen gas at STP?

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  1. 14 June, 00:41
    0
    5.15 L

    Step-by-step explanation:

    This looks like a case where we can use the Ideal Gas Law to calculate the volume.

    pV = nRT Divide both sides by p

    V = (nRT) / p

    dа ta:

    m = 7.25 g

    R = 0.083 14 L·atm·K⁻¹mol⁻¹

    T = (0 + 273.15) K = 273.15K

    p = 1 bar (Note: STP is 1 bar and 0°C)

    Calculations:

    (a) Moles of O₂

    n = m/M

    n = 7.25/32.00

    n = 0.2266 mol

    (b) Volume

    V = (0.2266 * 0.083 14 * 273.15) / 1

    V = 161.3/2.00

    V = 5.15 L
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