If you prepared a 3.25 M solution of sucrose (molar mass 342 g/mole),

a. How many moles are in 0.25 L of this solution?

b. How many grams is this?

We have 0.8125 moles sucrose in this solution. This is 277.9 grams of sucrose

Explanation:

Step 1: Data given

Molarity of a sucose solution = 3.25 M

Molar mass of sucrose = 342 g/mol

Step 2: Calculate moles sucrose

Moles sucrose = molarity sucrose solution * volume solution

Moles sucrose = 3.25 M * 0.25 L

Moles sucrose = 0.8125 moles sucrose

Step 3: Calculate mass of sucrose

Mass sucrose = moles sucrose * molar mass sucrose

Mass sucrose = 0.8125 moles * 342 g/mol

Mass sucrose = 277.9 grams

We have 0.8125 moles sucrose in this solution. This is 277.9 grams of sucrose

a. 0.8125 moles of sucrose

b. 277.8 g of sucrose

Explanation:

Consider these relation's value:

Molarity = Mol / Volume (L)

Mol = Molarity. Volume (L)

Volume (L) = Mol / Molarity

So, Molarity = 3.25M

Volume (L) = 0.25L

Molarity. Volume (L) = Mol → 3.25mol/L. 0.25L = 0.8125 mol

Let's convert the moles to mass → 0.8125 mol. 342 g / 1mol = 277.8 g of sucrose