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28 August, 17:23

How much of NaCl is in 1.90 L of 0.300 M

NaCl?

Answer in units of mol.

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Answers (1)
  1. 28 August, 18:21
    0
    The answer to your question is 0.57 moles

    Explanation:

    Data

    volume = 1.9 L

    [NaCl] = 0.3

    moles of NaCl = ?

    Process

    1. - To solve this problem use the formula of Molarity.

    Molarity = moles / volume (l)

    -Solve for moles

    moles = Molarity x volume

    -Substitution

    moles = 0.3 x 1.9

    -Result

    moles = 0.57

    -Conclusion

    There are 0.57 moles of NaCl in 1.90 L of a 0.3 M solution.
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