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26 January, 12:11

How much heat (energy) would be required to raise 20 grams of an unknown substance from 23 degrees Celsius to 33 degrees Celsius

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Answers (2)
  1. 26 January, 14:02
    0
    H = 0.2c J/Kg°C

    Explanation:

    m = 20g = 0.02kg, c=?, ∆t = 33-23 = 10

    H = mc∆t = 0.02*c*10 = 0.2c J/kg°C
  2. 26 January, 15:44
    0
    q = 836 J

    Explanation:

    The amount of heat required to raise 20 grams of an unknown substance from 23° Celsius to 33° Celsius can be computed below

    The specific heat capacity of the substance is not given, so let us assume the specific heat capacity of the substance is 4.18J/g°C.

    q = mcΔt

    where

    q = amount of heat energy

    m = mass

    c = specific heat capacity

    Δt = change in temperature

    Δt = 33°C - 23°C = 10°C

    q = mcΔt

    q = 20 g * 4.18 J/g°C * 10° C

    g cancel g and °C cancels °C. We are left with joules

    q = 836 J
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