Ask Question
7 August, 19:27

How many moles of O_{2} molecules are present in a 0.301 L sample of dry air at 0.0395 atm and 23.8 °C? (Oxygen constitutes 20.94% of the molecules in dry air.) (Enter your answer using either standard or scientific notation. For scientific notation, 6.02 x 10^{23} is written as 6.02E23.)

+5
Answers (1)
  1. 7 August, 21:51
    0
    The answer to your question is n = 4.89E-4

    Explanation:

    Data

    Volume = 0.301 L

    Pressure = 0.0395 atm

    Temperature = 23.8 °C

    moles = ?

    R = 0.082 atm L / mol°K

    Process

    1. - Convert the temperature to °K

    Temperature = 273 + 23.8

    = 296.8°K

    2. - Use the ideal gas law to find the answer

    PV = nRT

    -Solve for n

    n = PV / RT

    -Substitution

    n = (0.0395) (0.301) / (0.082) (296.8)

    -Simplification

    n = 0.011889 / 24.3376

    -Result

    n = 0.000488 or n = 4.89 x 10⁻⁴ or n = 4.89E-4
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “How many moles of O_{2} molecules are present in a 0.301 L sample of dry air at 0.0395 atm and 23.8 °C? (Oxygen constitutes 20.94% of the ...” in 📙 Chemistry if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers