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16 August, 12:12

What is the limiting reactant when 3 grams of propane is mixed with 10 grams of Oxygen?

C3H8 + O2 - > H2O + CO2

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  1. 16 August, 12:21
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    The answer to your question is Propane

    Explanation:

    Data

    mass of Propane = 3 g

    mass of Oxygen = 10 g

    limiting reactant = ?

    Balanced chemical reaction

    C₃H₈ + O₂ ⇒ H₂O + CO₂

    Process

    1. - Calculate the molar mass of the reactants

    C₃H₈ = (12 x 3) + (8 x 1) = 36 + 8 = 44 g

    O₂ = 16 x 2 = 32 g

    2. - Calculate the theoretical yield C₃H₈ / O₂ = 44/32 = 1.375

    3. - Calculate the experimental yield C₃H₈/O₂ = 3/10 = 0.3

    4. - Conclusion

    The limiting reactant is Propane because the experimental yield was lower than the theoretical yield.
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